We define the error of approximation at the kth iterate as εk = xk – α, k = 0, 1, 2,...
Subtracting (1.8) from (1.9), we obtain
xk 1 – α = φ(xk) – φ(α).....................2.0
= (xk – α)φ′(tk) (using the mean value theorem)........................ 2.1
or
......................2.3
Setting k = k – 1, we get
.........................2.4
Hence,
...........................2.5
Using (2.1) recursively, we get
............................2.6
The initial error ε0 is known and is a constant. We have
...............................2.7
Let
Then,
.......................2.8
For convergence, we require that | εk 1 | → 0 as k → ∞. This result is possible, if and only if c < 1. Therefore, the iteration method (1.9) converges, if and only if
or,
| φ′(x) | ≤ c < 1, for all x in the interval (a, b).
We can test this condition using x0, the initial approximation, before the computations are done.
Let us now check whether the methods (1.5), (1.6), (1.7) converge to a root in (0, 1) of the equation f(x) = x3 – 5x 1 = 0.